|x^2-1|=x+1

Lösung

x^{2} - 1 = x + 1

x = - 1 or x = 0 or x = 2

Schritte zur Lösung

x^{2} - 1 = x + 1

Finde positive und negative Intervalle

x \leq - 1, - 1 < x < 1, x \geq 1

Löse die Ungleichung für jedes Intervall

x = - 1 or x = 0 or x = 2

∣ j - 5 ∣ = j + 9

∣ 6 x - 2 ∣ = 0

∣ x + 5 ∣ 3 = 1

\frac{∣ x ∣}{5 - 3} = 4

∣ 8 x + 5 ∣ + 5 = 3