|x^2-4x-5|=7

Lösung

x^{2} - 4 x - 5 = 7

x = - 2 or x = 2 - 2 or x = 2 + 2 or x = 6

Dezimale

x = - 2, x = 0.58578 \dots, x = 3.41421 \dots, x = 6

Schritte zur Lösung

x^{2} - 4 x - 5 = 7

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} - 4 x - 5 = - 7 or x^{2} - 4 x - 5 = 7

x^{2} - 4 x - 5 = - 7 or x^{2} - 4 x - 5 = 7

(x = 2 - 2 or x = 2 + 2) or (x = - 2 or x = 6)

x = - 2 or x = 2 - 2 or x = 2 + 2 or x = 6

x^{2} - 4 = x - 2

∣ 4 x + 3 ∣ - 4 = 3 x

30 = ∣ y + 10 ∣

∣ x - 7 ∣ = c

∣ v ∣ = 6