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受欢迎的代数 >

3+sqrt(-x^2+4)=x^211

解答

3 + - x^{2} + 4 = x^{2} 11

解答

x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}

+1

十进制

x = 0.66644 \dots, x = - 0.66644 \dots

求解步骤

3 + - x^{2} + 4 = x^{2} \cdot 11

去除平方根

- x^{2} + 4 = 121 x^{4} - 66 x^{2} + 9

解

- x^{2} + 4 = 121 x^{4} - 66 x^{2} + 9 : x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}, x = \frac{65 - 19 5}{11 2}, x = - \frac{65 - 19 5}{11 2}

x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}, x = \frac{65 - 19 5}{11 2}, x = - \frac{65 - 19 5}{11 2}

验证解:

x = \frac{65 + 19 5}{11 2}

真

, x = - \frac{65 + 19 5}{11 2}

真

, x = \frac{65 - 19 5}{11 2}

假

, x = - \frac{65 - 19 5}{11 2}

假

解为

x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}

作图

流行的例子

(2x-7)^{3/4}+6=14

(2 x - 7)^{\frac{3}{4}} + 6 = 14

sqrt(x+5)-2=sqrt(5)-2

x + 5 - 2 = 5 - 2

3+sqrt(-x^2+4)=x^2-1

3 + - x^{2} + 4 = x^{2} - 1

\sqrt[3]{7v-8}=3

3 7 v - 8 = 3

0=2.5\sqrt[4]{x}-sqrt(x)-1

0 = 2.5 4 x - x - 1