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人気のある代数 >

b=(ax)/(1+asqrt(1-x^2))

解

b = \frac{a x}{1 + a 1 - x ^{2}}

解

x = \frac{b ( b ^{2} a ^{2} - b ^{2} + a ^{2} + 1 )}{a ( b ^{2} + 1 )}, x = \frac{b ( - b ^{2} a ^{2} - b ^{2} + a ^{2} + 1 )}{a ( b ^{2} + 1 )}

解答ステップ

b = \frac{a x}{1 + a 1 - x ^{2}}

以下で両辺を乗じる:

1 + a 1 - x^{2}

b (1 + a 1 - x^{2}) = \frac{a x}{1 + a 1 - x ^{2}} (1 + a 1 - x^{2})

簡素化

b (1 + a 1 - x^{2}) = a x

拡張

b (1 + a 1 - x^{2}) : b + ba 1 - x^{2}

b + ba 1 - x^{2} = a x

平方根を削除する

b^{2} a^{2} - b^{2} a^{2} x^{2} = a^{2} x^{2} - 2 ba x + b^{2}

解く

b^{2} a^{2} - b^{2} a^{2} x^{2} = a^{2} x^{2} - 2 ba x + b^{2} : x = \frac{b ( b ^{2} a ^{2} - b ^{2} + a ^{2} + 1 )}{a ( b ^{2} + 1 )}, x = \frac{b ( - b ^{2} a ^{2} - b ^{2} + a ^{2} + 1 )}{a ( b ^{2} + 1 )}

x = \frac{b ( b ^{2} a ^{2} - b ^{2} + a ^{2} + 1 )}{a ( b ^{2} + 1 )}, x = \frac{b ( - b ^{2} a ^{2} - b ^{2} + a ^{2} + 1 )}{a ( b ^{2} + 1 )}

グラフ

人気の例

2(x+1)^{2/3}=18

2 (x + 1)^{\frac{2}{3}} = 18

solvefor x,sqrt(y)+sqrt(x)=1

so l v e f or x, y + x = 1

solvefor x,f=sqrt(x)

so l v e f or x, f = x

sqrt(x-7)+sqrt(x)=1

x - 7 + x = 1

\sqrt[3]{4x-5}+7=8

3 4 x - 5 + 7 = 8