x(x-1)(x+8)>0

Lösung

x (x - 1) (x + 8) > 0

- 8 < x < 0 or x > 1

Intervall-Notation

(- 8, 0) \cup (1, \infty)

Schritte zur Lösung

x (x - 1) (x + 8) > 0

Identifiziere die Intervalle

- 8 < x < 0 or x > 1

x^{4} - 25 x^{2} + 144 < 0

\frac{2}{3} x - \frac{1}{2} = \frac{4}{3} - x

x^{2} + 5^{2} = 1 3^{2}

∣ 7 x ∣ > 42

s im pl i f y lo g_{7} (\frac{1}{7})