j(x)=sqrt(2-x)

Lösung

j (x) = 2 - x

x = \frac{- 1 + 1 + 8 j ^{2}}{2 j ^{2}} {j < 0 or j > 0}, x = \frac{- 1 - 1 + 8 j ^{2}}{2 j ^{2}}

Schritte zur Lösung

j (x) = 2 - x

Quadriere beide Seiten:

j^{2} x^{2} = 2 - x

j^{2} x^{2} = 2 - x

Löse

j^{2} x^{2} = 2 - x : x = \frac{- 1 + 1 + 8 j ^{2}}{2 j ^{2}}, x = \frac{- 1 - 1 + 8 j ^{2}}{2 j ^{2}}

x = \frac{- 1 + 1 + 8 j ^{2}}{2 j ^{2}}, x = \frac{- 1 - 1 + 8 j ^{2}}{2 j ^{2}}

Überprüfe die Lösungen:

x = \frac{- 1 + 1 + 8 j ^{2}}{2 j ^{2}} {j < 0 or j > 0}, x = \frac{- 1 - 1 + 8 j ^{2}}{2 j ^{2}}

Wahr

Die Lösungen sind

x = \frac{- 1 + 1 + 8 j ^{2}}{2 j ^{2}} {j < 0 or j > 0}, x = \frac{- 1 - 1 + 8 j ^{2}}{2 j ^{2}}

3 3 x - 2 = \frac{1}{2}

x^{2} + 3 x + 2 = x + 2

x - 2 - x + 4 = 0

x^{2} - 12 = - x

3 x + 13 = x + 3