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人気のある代数 >

(x^2-x)^2-5(x^2-x)+6=0

解

(x^{2} - x)^{2} - 5 (x^{2} - x) + 6 = 0

解

x = - 1, x = 2, x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

+1

十進法表記

x = - 1, x = 2, x = 2.30277 \dots, x = - 1.30277 \dots

解答ステップ

(x^{2} - x)^{2} - 5 (x^{2} - x) + 6 = 0

拡張

(x^{2} - x)^{2} - 5 (x^{2} - x) + 6 : x^{4} - 2 x^{3} - 4 x^{2} + 5 x + 6

x^{4} - 2 x^{3} - 4 x^{2} + 5 x + 6 = 0

因数

x^{4} - 2 x^{3} - 4 x^{2} + 5 x + 6 : (x + 1) (x - 2) (x^{2} - x - 3)

(x + 1) (x - 2) (x^{2} - x - 3) = 0

零因子の原則を使用:

ab = 0

ならば

a = 0

または

b = 0

x + 1 = 0 or x - 2 = 0 or x^{2} - x - 3 = 0

解く

x + 1 = 0 : x = - 1

解く

x - 2 = 0 : x = 2

解く

x^{2} - x - 3 = 0 : x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

解答は

x = - 1, x = 2, x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

グラフ

人気の例

6x^4-x^3-26x+4x+8=0

6 x^{4} - x^{3} - 26 x + 4 x + 8 = 0

t^{4} - t^{2} = 2

(2x)^4+(x^2-1)^2=-1

(2 x)^{4} + (x^{2} - 1)^{2} = - 1

12 x^{3} = 4

solvefor x,0.05=(1+x)^{11}-1

so l v e f or x, 0.05 = (1 + x)^{11} - 1