(1-m)^3= 1/3

Lösung

(1 - m)^{3} = \frac{1}{3}

m = - 3 \frac{1}{3} + 1, m = \frac{3 ^{\frac{2}{3}} ( 1 + 2 3 3 )}{6} - i \frac{6 3}{2}, m = \frac{3 ^{\frac{2}{3}} ( 1 + 2 3 3 )}{6} + i \frac{6 3}{2}

Schritte zur Lösung

(1 - m)^{3} = \frac{1}{3}

Für

g^{3} (x) = f (a)

sind die Lösungen

g (x) = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

Löse

1 - m = 3 \frac{1}{3} : m = - 3 \frac{1}{3} + 1

Löse

1 - m = 3 \frac{1}{3} \frac{- 1 + 3 i}{2} : m = \frac{3 ^{\frac{2}{3}} ( 1 + 2 3 3 )}{6} - i \frac{6 3}{2}

Löse

1 - m = 3 \frac{1}{3} \frac{- 1 - 3 i}{2} : m = \frac{3 ^{\frac{2}{3}} ( 1 + 2 3 3 )}{6} + i \frac{6 3}{2}

Die Lösungen sind

m = - 3 \frac{1}{3} + 1, m = \frac{3 ^{\frac{2}{3}} ( 1 + 2 3 3 )}{6} - i \frac{6 3}{2}, m = \frac{3 ^{\frac{2}{3}} ( 1 + 2 3 3 )}{6} + i \frac{6 3}{2}

x^{1} + 2 x^{2} + x^{3} = - 1

4 x^{3} - 54 x^{2} + 180 x - 125 = 0

b^{4} - 6 b^{3} - 5 b^{2} + 42 b + 40 = 0

3 x^{3} + 13 x^{2} - 10 x = 0

x^{3} = x - 2