e^{(ln(0.4))t}=0.7

Lösung

e^{(l n (0.4)) t} = 0.7

t = \frac{ln ( 0.7 )}{ln ( 0.4 )}

Dezimale

t = 0.38925 \dots

Schritte zur Lösung

e^{(l n (0.4)) t} = 0.7

Wende Exponentenregel an

ln (0.4) t = ln (0.7)

Löse

ln (0.4) t = ln (0.7) : t = \frac{ln ( 0.7 )}{ln ( 0.4 )}

t = \frac{ln ( 0.7 )}{ln ( 0.4 )}

so l v e f or n, 128 = 2^{n - 1}

e^{x + 3} = 2

(\frac{1}{2})^{x} = - 4

2^{x} + 2^{x} + 2^{x} = 192

(\frac{1}{2})^{5 - 2 x} = 2^{5 x - 2}