2/3 =e^{-k(20)}

Lösung

\frac{2}{3} = e^{- k (20)}

k = - \frac{ln ( \frac{2}{3} )}{20}

Dezimale

k = 0.02027 \dots

Schritte zur Lösung

\frac{2}{3} = e^{- k (20)}

Wende Exponentenregel an

ln (\frac{2}{3}) = - k \cdot 20

Löse

ln (\frac{2}{3}) = - k \cdot 20 : k = - \frac{ln ( \frac{2}{3} )}{20}

k = - \frac{ln ( \frac{2}{3} )}{20}

9 = 5 + 16 e^{- 0.01102 t}

2 e^{x^{2} - 2} = 4

2^{x + 2} = 1 6^{x}

8 = 51 4^{x}

5^{2 r - 3} = 25