4^{x+5}=4^{3x-2}

Lösung

4^{x + 5} = 4^{3 x - 2}

x = \frac{7}{2}

Dezimale

x = 3.5

Schritte zur Lösung

4^{x + 5} = 4^{3 x - 2}

Wende Exponentenregel an

x + 5 = 3 x - 2

Löse

x + 5 = 3 x - 2 : x = \frac{7}{2}

x = \frac{7}{2}

43 = 72 + (39 - 72) e^{k \cdot 1}

1 6^{x} = 6 4^{x + 4}

x^{- \frac{1}{700} (x)} = 94667

2^{x} = 3^{x + 3}

\frac{93}{151} = e^{- 12 k}