5*25^{x+2}=125^{2x}

解答

5 \cdot 2 5^{x + 2} = 12 5^{2 x}

x = \frac{5}{4}

十进制

x = 1.25

求解步骤

5 \cdot 2 5^{x + 2} = 12 5^{2 x}

使用指数运算法则

2 (x + 2) + 1 = 6 x

解

2 (x + 2) + 1 = 6 x : x = \frac{5}{4}

x = \frac{5}{4}

7^{5 x^{2} - 42 x} = 1 0^{125 - 42 x}

so l v e f or t, e^{k t} = \frac{1}{7}

3 ∣ 2^{x} - 1 ∣ = 2^{x}

3 x e^{x} + x^{2} e^{x} = 0

e^{4 x} = 2