8^{3x+2}=16^{x-4}

Lösung

8^{3 x + 2} = 1 6^{x - 4}

x = - \frac{22}{5}

Dezimale

x = - 4.4

Schritte zur Lösung

8^{3 x + 2} = 1 6^{x - 4}

Wende Exponentenregel an

3 (3 x + 2) = 4 (x - 4)

Löse

3 (3 x + 2) = 4 (x - 4) : x = - \frac{22}{5}

x = - \frac{22}{5}

(625)^{x} = 125

95 = 2 3^{x}

1 8^{x^{2} + 4 x + 4} = 1 8^{9 x + 18}

9^{2 x - 1} = 2 7^{x}

89 = 1 5^{x}