e^{x+1}=2^{x+2}

Lösung

e^{x + 1} = 2^{x + 2}

x = \frac{2 ln ( 2 ) - 1}{1 - ln ( 2 )}

Dezimale

x = 1.25889 \dots

Schritte zur Lösung

e^{x + 1} = 2^{x + 2}

Wende Exponentenregel an

x + 1 = (x + 2) ln (2)

Löse

x + 1 = (x + 2) ln (2) : x = \frac{2 ln ( 2 ) - 1}{1 - ln ( 2 )}

x = \frac{2 ln ( 2 ) - 1}{1 - ln ( 2 )}

2^{n} = 4

2^{1 + x} = 5^{x}

3 x^{2} e^{x} + x^{3} e^{x} = 0

133.9 = \frac{133.9}{1 + 2 e ^{- t}}

e^{x^{2} - 4 x} = \frac{1}{e ^{2 x}}