2^{x-3}=8^{x+1}

Lösung

2^{x - 3} = 8^{x + 1}

x = - 3

Schritte zur Lösung

2^{x - 3} = 8^{x + 1}

Wende Exponentenregel an

x - 3 = 3 (x + 1)

Löse

x - 3 = 3 (x + 1) : x = - 3

x = - 3

x^{x} 2 + 2 x - 8 = 0

7^{2 x - 1} = 5^{x}

e^{3 t + 6} = 3 e^{6 - t}

25 = 5 (8)^{- 3 x - 1}

7^{x - 1} = 5