12^{2x}=4*3^{x+1}

Lösung

1 2^{2 x} = 4 \cdot 3^{x + 1}

x = \frac{ln ( 12 )}{ln ( 48 )}

Dezimale

x = 0.64189 \dots

Schritte zur Lösung

1 2^{2 x} = 4 \cdot 3^{x + 1}

Wende Exponentenregel an

2 x ln (12) = ln (4) + (x + 1) ln (3)

Löse

2 x ln (12) = ln (4) + (x + 1) ln (3) : x = \frac{ln ( 12 )}{ln ( 48 )}

x = \frac{ln ( 12 )}{ln ( 48 )}

6^{(x + 2)} = 21

3^{2 - x} = \frac{1}{81}

e^{x} = 2 x + 3

2^{3 x - 4} = 10

5^{2 x} = 625