7^{3x-2}=13^{x+1}

解答

7^{3 x - 2} = 1 3^{x + 1}

x = \frac{ln ( 637 )}{3 ln ( 7 ) - ln ( 13 )}

十进制

x = 1.97286 \dots

求解步骤

7^{3 x - 2} = 1 3^{x + 1}

使用指数运算法则

(3 x - 2) ln (7) = (x + 1) ln (13)

解

(3 x - 2) ln (7) = (x + 1) ln (13) : x = \frac{ln ( 637 )}{3 ln ( 7 ) - ln ( 13 )}

x = \frac{ln ( 637 )}{3 ln ( 7 ) - ln ( 13 )}

5^{(2 x)} - 6 (5^{x}) + 5 = 0

so l v e f or I, x = e^{I n (7)}

0.1 e^{0.1 x} = 0.5

5 = 1000 (1 - \frac{1}{3})^{x}

(2)^{x} = 4