solvefor x,2^x+3^y=41

解

解く

x, 2^{x} + 3^{y} = 41

x = \frac{ln ( 41 - 3 ^{y} )}{ln ( 2 )}

解答ステップ

2^{x} + 3^{y} = 41

3^{y}

を右側に移動します

2^{x} = 41 - 3^{y}

指数の規則を適用する

x ln (2) = ln (41 - 3^{y})

解く

x ln (2) = ln (41 - 3^{y}) : x = \frac{ln ( 41 - 3 ^{y} )}{ln ( 2 )}

x = \frac{ln ( 41 - 3 ^{y} )}{ln ( 2 )}