7^{x+2}=17

Lösung

7^{x + 2} = 17

x = \frac{ln ( 17 )}{ln ( 7 )} - 2

Dezimale

x = - 0.54401 \dots

Schritte zur Lösung

7^{x + 2} = 17

Wende Exponentenregel an

(x + 2) ln (7) = ln (17)

Löse

(x + 2) ln (7) = ln (17) : x = \frac{ln ( 17 )}{ln ( 7 )} - 2

x = \frac{ln ( 17 )}{ln ( 7 )} - 2

(3^{x})^{2} - 3^{x + 1} + 2 = 0

2^{y} = 24

3^{x^{2}} - 9^{6 - 2 x} = 0

e^{3 l n (x)} = 125

5^{3 x - 3} = 1