4^x*2^{x^2}=16^2

Lösung

4^{x} \cdot 2^{x^{2}} = 1 6^{2}

x = 2, x = - 4

Schritte zur Lösung

4^{x} \cdot 2^{x^{2}} = 1 6^{2}

Wende Exponentenregel an

2 x + x^{2} = 8

Löse

2 x + x^{2} = 8 : x = 2, x = - 4

x = 2, x = - 4

3^{x} - 2 = 12

e^{2 x - 1} = 4

2^{x} + 2^{x + 1} = 12

1.4 = 1. 1^{x}

2^{x + 2} = \frac{1}{32}