(4x+1)/(2(8x+6))=2(4x+3)

解

\frac{4 x + 1}{2 ( 8 x + 6 )} = 2 (4 x + 3)

x = - \frac{47}{64} + i \frac{3 7}{64}, x = - \frac{47}{64} - i \frac{3 7}{64}

解答ステップ

\frac{4 x + 1}{2 ( 8 x + 6 )} = 2 (4 x + 3)

以下で両辺を乗じる:

2 (8 x + 6)

4 x + 1 = 4 (4 x + 3) (8 x + 6)

解く

4 x + 1 = 4 (4 x + 3) (8 x + 6) : x = - \frac{47}{64} + i \frac{3 7}{64}, x = - \frac{47}{64} - i \frac{3 7}{64}

x = - \frac{47}{64} + i \frac{3 7}{64}, x = - \frac{47}{64} - i \frac{3 7}{64}