2/(5x)+6< 3/5-2x

Lösung

\frac{2}{5 x} + 6 < \frac{3}{5} - 2 x

x < \frac{- 27 - 649}{20} or \frac{649 - 27}{20} < x < 0

Intervall-Notation

(- \infty, \frac{- 27 - 649}{20}) \cup (\frac{649 - 27}{20}, 0)

Dezimale

x < - 2.62377 \dots or - 0.07622 \dots < x < 0

Schritte zur Lösung

\frac{2}{5 x} + 6 < \frac{3}{5} - 2 x

Rewrite in standard form

\frac{10 x ^{2} + 27 x + 2}{x} < 0

Faktor

10 x^{2} + 27 x + 2 : (x - \frac{- 27 + 649}{20}) (x - \frac{- 27 - 649}{20})

\frac{( x - \frac{- 27 + 649}{20} ) ( x - \frac{- 27 - 649}{20} )}{x} < 0

Identifiziere die Intervalle

x < \frac{- 27 - 649}{20} or \frac{649 - 27}{20} < x < 0

25 y^{2} - 81 = 0

5 \geq \frac{1}{5} (- 10) - 5

(x - 6)^{2} = 20 - 2 x

s im pl i f y (\frac{a}{b ^{3}})^{4}

s im pl i f y (- 243)^{\frac{4}{5}}