6/(x^2+1)=3x^2

解答

\frac{6}{x ^{2} + 1} = 3 x^{2}

x = 1, x = - 1, x = 2 i, x = - 2 i

求解步骤

\frac{6}{x ^{2} + 1} = 3 x^{2}

在两边乘以

x^{2} + 1

6 = 3 x^{2} (x^{2} + 1)

解

6 = 3 x^{2} (x^{2} + 1) : x = 1, x = - 1, x = 2 i, x = - 2 i

x = 1, x = - 1, x = 2 i, x = - 2 i

so l v e f or F, \frac{b}{F - h ^{2}} = r

\frac{x + 3}{2 x - 1} = 4 - x

\frac{3}{x + 2} - \frac{4}{x - 2} = 5

\frac{w}{2 w - 3} = \frac{4}{w}

so l v e f or g, g^{- 1} (k + 1) = 2 k