7y^2-35y=0

解

7 y^{2} - 35 y = 0

y = 5, y = 0

解答ステップ

7 y^{2} - 35 y = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 35 ) \pm ( - 35 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 35)^{2} - 4 \cdot 7 \cdot 0 = 35

y_{1, 2} = \frac{- ( - 35 ) \pm 35}{2 \cdot 7}

解を分離する

y_{1} = \frac{- ( - 35 ) + 35}{2 \cdot 7}, y_{2} = \frac{- ( - 35 ) - 35}{2 \cdot 7}

y = \frac{- ( - 35 ) + 35}{2 \cdot 7} : 5

y = \frac{- ( - 35 ) - 35}{2 \cdot 7} : 0

二次equationの解:

y = 5, y = 0