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受欢迎的代数 >

(4x+4)(ax-1)-x^2+4=bx

解答

(4 x + 4) (a x - 1) - x^{2} + 4 = b x

解答

x = 0, x = - \frac{4 a - 4 - b}{4 a - 1}; a \neq = \frac{1}{4}

求解步骤

(4 x + 4) (a x - 1) - x^{2} + 4 = b x

展开

(4 x + 4) (a x - 1) - x^{2} + 4 : 4 a x^{2} - x^{2} + 4 a x - 4 x

4 a x^{2} - x^{2} + 4 a x - 4 x = b x

将

b x

para o lado esquerdo

4 a x^{2} - x^{2} + 4 a x - 4 x - b x = 0

改写成标准形式

a x^{2} + b x + c = 0

(4 a - 1) x^{2} + (4 a - 4 - b) x = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 4 a - 4 - b ) \pm ( 4 a - 4 - b ) ^{2} - 4 ( 4 a - 1 ) \cdot 0}{2 ( 4 a - 1 )}

化简

(4 a - 4 - b)^{2} - 4 (4 a - 1) \cdot 0 : 4 a - b - 4

x_{1, 2} = \frac{- ( 4 a - 4 - b ) \pm ( 4 a - b - 4 )}{2 ( 4 a - 1 )}; a \neq = \frac{1}{4}

将解分隔开

x_{1} = \frac{- ( 4 a - 4 - b ) + 4 a - b - 4}{2 ( 4 a - 1 )}, x_{2} = \frac{- ( 4 a - 4 - b ) - ( 4 a - b - 4 )}{2 ( 4 a - 1 )}

x = \frac{- ( 4 a - 4 - b ) + 4 a - b - 4}{2 ( 4 a - 1 )} : 0

x = \frac{- ( 4 a - 4 - b ) - ( 4 a - b - 4 )}{2 ( 4 a - 1 )} : - \frac{4 a - 4 - b}{4 a - 1}

二次方程组的解是:

x = 0, x = - \frac{4 a - 4 - b}{4 a - 1}; a \neq = \frac{1}{4}

作图

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