What are the solutions to the equation 64az^2-81a^3=0 ?

The solutions to the equation 64az^2-81a^3=0 are z=(9a)/8 ,z=-(9a)/8 ;\quad a\ne 0

Find the zeros of 64az^2-81a^3=0

The zeros of 64az^2-81a^3=0 are z=(9a)/8 ,z=-(9a)/8 ;\quad a\ne 0

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64 a z^{2} - 81 a^{3} = 0

z = \frac{9 a}{8}, z = - \frac{9 a}{8}; a \neq = 0

Solution steps

64 a z^{2} - 81 a^{3} = 0

Move

81 a^{3}

to the right side

64 a z^{2} = 81 a^{3}

Divide both sides by

64 a; a \neq = 0

z^{2} = \frac{81 a ^{2}}{64}; a \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = \frac{81 a ^{2}}{64}, z = - \frac{81 a ^{2}}{64}; a \neq = 0

Simplify

\frac{81 a ^{2}}{64} : \frac{9 a}{8}

Simplify

- \frac{81 a ^{2}}{64} : - \frac{9 a}{8}

z = \frac{9 a}{8}, z = - \frac{9 a}{8}; a \neq = 0

- 0.005 x^{2} + 0.101 x - 0.193 = 0

x^{2} - 6 x + 5 = - x^{2} + 4 x

so l v e f or x, z = - x^{2} - 2 y

co m pl e t es q u a re x^{2} + 5 x + 2 = - 4

3 x (x - 2) = - 7

What are the solutions to the equation 64az^2-81a^3=0 ?
The solutions to the equation 64az^2-81a^3=0 are z=(9a)/8 ,z=-(9a)/8 ;\quad a\ne 0
Find the zeros of 64az^2-81a^3=0
The zeros of 64az^2-81a^3=0 are z=(9a)/8 ,z=-(9a)/8 ;\quad a\ne 0