What are the solutions to the equation 5x^2-38x+48=0 ?

The solutions to the equation 5x^2-38x+48=0 are x=6,x= 8/5

Find the zeros of 5x^2-38x+48=0

The zeros of 5x^2-38x+48=0 are x=6,x= 8/5

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5 x^{2} - 38 x + 48 = 0

x = 6, x = \frac{8}{5}

Decimal Notation

x = 6, x = 1.6

Solution steps

5 x^{2} - 38 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 38 ) \pm ( - 38 ) ^{2} - 4 \cdot 5 \cdot 48}{2 \cdot 5}

(- 38)^{2} - 4 \cdot 5 \cdot 48 = 22

x_{1, 2} = \frac{- ( - 38 ) \pm 22}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 38 ) + 22}{2 \cdot 5}, x_{2} = \frac{- ( - 38 ) - 22}{2 \cdot 5}

x = \frac{- ( - 38 ) + 22}{2 \cdot 5} : 6

x = \frac{- ( - 38 ) - 22}{2 \cdot 5} : \frac{8}{5}

The solutions to the quadratic equation are:

x = 6, x = \frac{8}{5}

3 x + 6 = - 4 x - 8

ln ∣ 4 ∣

\frac{3 - \frac{3}{a + 2}}{\frac{1}{a + 2} + \frac{a}{3}}

x^{4} - 2 x^{2} - 35

15 = g - 5

What are the solutions to the equation 5x^2-38x+48=0 ?
The solutions to the equation 5x^2-38x+48=0 are x=6,x= 8/5
Find the zeros of 5x^2-38x+48=0
The zeros of 5x^2-38x+48=0 are x=6,x= 8/5