erweitern ((6A+2k+1)(k+1))/k

Lösung

erweitern

\frac{( 6 A + 2 k + 1 ) ( k + 1 )}{k}

6 A + \frac{6 A}{k} + 2 k + 3 + \frac{1}{k}

Schritte zur Lösung

\frac{( 6 A + 2 k + 1 ) ( k + 1 )}{k}

Multipliziere aus

(6 A + 2 k + 1) (k + 1) : 6 A k + 6 A + 2 k^{2} + 3 k + 1

= \frac{6 A k + 6 A + 2 k ^{2} + 3 k + 1}{k}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 A k + 6 A + 2 k ^{2} + 3 k + 1}{k} = \frac{6 A k}{k} + \frac{6 A}{k} + \frac{2 k ^{2}}{k} + \frac{3 k}{k} + \frac{1}{k}

= \frac{6 A k}{k} + \frac{6 A}{k} + \frac{2 k ^{2}}{k} + \frac{3 k}{k} + \frac{1}{k}

Streiche

\frac{6 A k}{k} : 6 A

= 6 A + \frac{6 A}{k} + \frac{2 k ^{2}}{k} + \frac{3 k}{k} + \frac{1}{k}

Streiche

\frac{2 k ^{2}}{k} : 2 k

= 6 A + \frac{6 A}{k} + 2 k + \frac{3 k}{k} + \frac{1}{k}

Streiche

\frac{3 k}{k} : 3

= 6 A + \frac{6 A}{k} + 2 k + 3 + \frac{1}{k}

e x p an d (4 x + 4 δ x) \cdot (x^{2} - 4)

e x p an d \frac{24}{( s - 2 ) ^{4}}

e x p an d 2 (- 3 x^{2})

e x p an d \frac{4 x ^{2} - 8 x + 4}{( x + 1 ) ^{2}}

e x p an d \frac{( - 2 y + 2 ) ^{3}}{3}