展开 (6-b)tan(50)

解答

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(6 - b) tan (5 0^{\circ})

6 tan (5 0^{\circ}) - tan (5 0^{\circ}) b

求解步骤

(6 - b) tan (5 0^{\circ})

= tan (5 0^{\circ}) (6 - b)

使用分配律:

a (b - c) = ab - a c

a = tan (5 0^{\circ}), b = 6, c = b

= tan (5 0^{\circ}) \cdot 6 - tan (5 0^{\circ}) b

= 6 tan (5 0^{\circ}) - tan (5 0^{\circ}) b

e x p an d π r^{2} (r - 7)

e x p an d (2 x + 3 y = 7,) (6 x - y = 1)

e x p an d (1 + 5) e^{4}

e x p an d 4 (2 x + 3 y = 53)

e x p an d \frac{s}{( s ^{2} + 2 ) ^{2}}