展开 ((tx+t)^2)/4

解答

展开

\frac{( t x + t ) ^{2}}{4}

\frac{t ^{2} x ^{2}}{4} + \frac{t ^{2} x}{2} + \frac{t ^{2}}{4}

求解步骤

\frac{( t x + t ) ^{2}}{4}

(t x + t)^{2} = t^{2} x^{2} + 2 t^{2} x + t^{2}

= \frac{t ^{2} x ^{2} + 2 t ^{2} x + t ^{2}}{4}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{t ^{2} x ^{2} + 2 t ^{2} x + t ^{2}}{4} = \frac{t ^{2} x ^{2}}{4} + \frac{2 t ^{2} x}{4} + \frac{t ^{2}}{4}

= \frac{t ^{2} x ^{2}}{4} + \frac{2 t ^{2} x}{4} + \frac{t ^{2}}{4}

消掉

\frac{2 t ^{2} x}{4} : \frac{t ^{2} x}{2}

= \frac{t ^{2} x ^{2}}{4} + \frac{t ^{2} x}{2} + \frac{t ^{2}}{4}

e x p an d (1 + cos (2 θ)) 3 = sin (2 θ)

e x p an d - 2 (2 x - 1 + 1 = 17 - 4 x)

e x p an d (2 + 6 i,) (- 4 + 3 i,)

e x p an d ((x - 2) (x - 3)) + (x^{2} - 1)

e x p an d 3 (x - 1 = 30)