展开 1/((t^3+4)^5)

解答

展开

\frac{1}{( t ^{3} + 4 ) ^{5}}

\frac{1}{t ^{15} + 20 t ^{12} + 160 t ^{9} + 640 t ^{6} + 1280 t ^{3} + 1024}

求解步骤

\frac{1}{( t ^{3} + 4 ) ^{5}}

(t^{3} + 4)^{5} = t^{15} + 20 t^{12} + 160 t^{9} + 640 t^{6} + 1280 t^{3} + 1024

= \frac{1}{t ^{15} + 20 t ^{12} + 160 t ^{9} + 640 t ^{6} + 1280 t ^{3} + 1024}

e x p an d \frac{( x - 2 ) ( x + 1 )}{x ^{2}}

e x p an d 1 6^{2}

e x p an d 20 (1 + x) e^{(4) (x^{3}) (1 + x)}

e x p an d e^{(t - 6)} h (t - 6)

e x p an d \frac{- 3 + 2 x}{3 ( - 1 + x )}