erweitern ((2x-4)^4)/(81)

Lösung

erweitern

\frac{( 2 x - 4 ) ^{4}}{81}

\frac{16 x ^{4}}{81} - \frac{128 x ^{3}}{81} + \frac{128 x ^{2}}{27} - \frac{512 x}{81} + \frac{256}{81}

Schritte zur Lösung

\frac{( 2 x - 4 ) ^{4}}{81}

(2 x - 4)^{4} = 16 x^{4} - 128 x^{3} + 384 x^{2} - 512 x + 256

= \frac{16 x ^{4} - 128 x ^{3} + 384 x ^{2} - 512 x + 256}{81}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{4} - 128 x ^{3} + 384 x ^{2} - 512 x + 256}{81} = \frac{16 x ^{4}}{81} - \frac{128 x ^{3}}{81} + \frac{384 x ^{2}}{81} - \frac{512 x}{81} + \frac{256}{81}

= \frac{16 x ^{4}}{81} - \frac{128 x ^{3}}{81} + \frac{384 x ^{2}}{81} - \frac{512 x}{81} + \frac{256}{81}

Streiche

\frac{384 x ^{2}}{81} : \frac{128 x ^{2}}{27}

= \frac{16 x ^{4}}{81} - \frac{128 x ^{3}}{81} + \frac{128 x ^{2}}{27} - \frac{512 x}{81} + \frac{256}{81}

e x p an d 6 (x - 3) x^{'}

e x p an d \frac{( 2 x + 5 ) ( 9 x - 2 )}{( 2 )}

e x p an d \frac{z p}{1 - z ( 1 - p )}

e x p an d \frac{1}{x ^{2} ( x - 3 ) ( x + 1 )}

e x p an d \frac{x ^{2} - b x + 2}{( x - b ) ^{2}}