展開する (1/(2a+b=-2,))(a-2b=8,)

解

展開する

(\frac{1}{2 a + b = - 2 ,}) (a - 2 b = 8,)

(\frac{1}{2 a + = b - 2 ,}) a - 2 (\frac{1}{2 a + = b - 2 ,}) b = 8,

解答ステップ

(\frac{1}{2 a + b = - 2 ,}) (a - 2 b = 8,)

= (\frac{1}{2 a + = b - 2 ,}) (a - 2 \cdot 8 =, b)

分配法則を適用する:

a (b - c) = ab - a c

a = (\frac{1}{2 a + b = - 2 ,}), b = a, c = 2 b = 8,

(\frac{1}{2 a + b = - 2 ,}) a - (\frac{1}{2 a + b = - 2 ,}) \cdot 2 b = 8,

(\frac{1}{2 a + = b - 2 ,}) a - 2 (\frac{1}{2 a + = b - 2 ,}) b = 8,