展开 lm(4+ae^{bt})

解答

展开

l m (4 + a e^{b t})

4 l m + l e^{b t} ma

求解步骤

l m (4 + a e^{b t})

= l m (4 + e^{b t} a)

使用分配律:

a (b + c) = ab + a c

a = l m, b = 4, c = a e^{b t}

= l m \cdot 4 + l ma e^{b t}

= 4 l m + l e^{b t} ma

\frac{d}{d x} ((z) (3 x y + z^{2} x - 7 y))

e x p an d (3 x + 2) (1 + 1 = 0)

e x p an d f (x) (ln (x) - x^{2})^{3}

s im pl i f y (\frac{1}{x} \circ 7 - x) (x)

e x p an d \frac{5}{( x + 1 ) ^{2}}