faktorisieren 9z^{8n}-16

Lösung

faktorisieren

9 z^{8 n} - 16

(3 z^{4 n} + 4) (3 z^{4 n} - 4)

Schritte zur Lösung

9 z^{8 n} - 16

Schreibe

9 z^{8 n}

um:

(3 z^{4 n})^{2}

= (3 z^{4 n})^{2} - 16

Schreibe

16

um:

4^{2}

= (3 z^{4 n})^{2} - 4^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(3 z^{4 n})^{2} - 4^{2} = (3 z^{4 n} + 4) (3 z^{4 n} - 4)

= (3 z^{4 n} + 4) (3 z^{4 n} - 4)

f a c t or 4 (- 2 + 4 i)

f a c t or - 0.06 x^{2} + 1.31 x + 1.38

f a c t or 56 b w - 49 bk + 40 x w - 35 x k

f a c t or 20 n + 25 n

f a c t or 12 x^{2} - 11 x - 5^{2}