faktorisieren (4-m^3)(2+m-1)

Lösung

faktorisieren

(4 - m^{3}) (2 + m - 1)

- (m - 34) (m^{2} + 34 m + 4^{\frac{2}{3}}) (m + 1)

Schritte zur Lösung

(4 - m^{3}) (2 + m - 1)

Faktorisiere

4 - m^{3} : - (m - 34) (m^{2} + 34 m + 4^{\frac{2}{3}})

= - (m - 34) (m^{2} + 34 m + 4^{\frac{2}{3}}) (2 + m - 1)

Fasse zusammen

= - (m - 34) (m^{2} + 34 m + 4^{\frac{2}{3}}) (m + 1)

f a c t or 4 a^{2} x + 4 a^{2} y - b^{2} x - b^{2} y

f a c t or 4 81 x^{8}

f (t) = 3 sin^{(2)} (t)

f a c t or (4.7 x^{10} - 4) - (5.3 x^{102})

f a c t or 8 cos^{3} (x) - 4 cos (x) + 1