因式分解 (x-1)(a-b)(2x-5)(a-b)

解答

因式分解

(x - 1) (a - b) (2 x - 5) (a - b)

(x - 1) (2 x - 5) (a - b)^{2}

求解步骤

(x - 1) (a - b) (2 x - 5) (a - b)

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

(a - b) (a - b) = (a - b)^{1 + 1}

= (x - 1) (2 x - 5) (a - b)^{1 + 1}

数字相加:

1 + 1 = 2

= (x - 1) (2 x - 5) (a - b)^{2}

f a c t or 2 x^{2} + 7 + 3

s im pl i f y 1105.43 - (x) (67.72)

f a c t or 100 - a^{8}

f a c t or 10000 (1.00016438)^{10220}

f a c t or - x^{2} + 7 + 1