What is factor 8x^9y^6+z^{15} ?

The solution to factor 8x^9y^6+z^{15} is (2x^3y^2+z^5)(4x^6y^4-2x^3y^2z^5+z^{10})

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factor 8x^9y^6+z^{15}

factor

8 x^{9} y^{6} + z^{15}

(2 x^{3} y^{2} + z^{5}) (4 x^{6} y^{4} - 2 x^{3} y^{2} z^{5} + z^{10})

Solution steps

8 x^{9} y^{6} + z^{15}

Rewrite

8 x^{9} y^{6}

(2 x^{3} y^{2})^{3}

= (2 x^{3} y^{2})^{3} + z^{15}

Apply exponent rule:

a^{b c} = (a^{b})^{c}

z^{15} = (z^{5})^{3}

= (2 x^{3} y^{2})^{3} + (z^{5})^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 x^{3} y^{2})^{3} + (z^{5})^{3} = (2 x^{3} y^{2} + z^{5}) ((2 x^{3} y^{2})^{2} - 2 x^{3} y^{2} z^{5} + z^{10})

= (z^{5} + 2 x^{3} y^{2}) ((2 x^{3} y^{2})^{2} - z^{5} 2 x^{3} y^{2} + z^{10})

Simplify

(2 x^{3} y^{2} + z^{5}) ((2 x^{3} y^{2})^{2} - 2 x^{3} y^{2} z^{5} + z^{10}) : (2 x^{3} y^{2} + z^{5}) (4 x^{6} y^{4} - 2 x^{3} y^{2} z^{5} + z^{10})

= (2 x^{3} y^{2} + z^{5}) (4 x^{6} y^{4} - 2 x^{3} y^{2} z^{5} + z^{10})

f (x) = x - 1

(cos (2 t))^{2}

(m - n)^{2} + 6 (m - n) + 9

- (1)

6 a^{2} - 4 a c - 15 ab + 10 b c

What is factor 8x^9y^6+z^{15} ?
The solution to factor 8x^9y^6+z^{15} is (2x^3y^2+z^5)(4x^6y^4-2x^3y^2z^5+z^{10})