What is factor (2x-1)^2+8(2x-1)+12 ?

The solution to factor (2x-1)^2+8(2x-1)+12 is (2x+1)(2x+5)

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factor (2x-1)^2+8(2x-1)+12

factor

(2 x - 1)^{2} + 8 (2 x - 1) + 12

(2 x + 1) (2 x + 5)

Solution steps

(2 x - 1)^{2} + 8 (2 x - 1) + 12

Expand

(2 x - 1)^{2} + 8 (2 x - 1) + 12 : 4 x^{2} + 12 x + 5

= 4 x^{2} + 12 x + 5

Factor

4 x^{2} + 12 x + 5 : (2 x + 1) (2 x + 5)

= (2 x + 1) (2 x + 5)

a x - 5 b x + 5 a y - 25 b y

(sin (θ))^{2}

- 1 - x + 2 a (1 - x)

r^{3} + (r + 3)^{5}

(x - 1) - (2 x^{2})

What is factor (2x-1)^2+8(2x-1)+12 ?
The solution to factor (2x-1)^2+8(2x-1)+12 is (2x+1)(2x+5)