vereinfachen (2x^{-1}y^2)^2

Lösung

vereinfachen

(2 x^{- 1} y^{2})^{2}

\frac{4 y ^{4}}{x ^{2}}

Schritte zur Lösung

(2 x^{- 1} y^{2})^{2}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x^{- 1} y^{2})^{2} = 2^{2} (x^{- 1})^{2} (y^{2})^{2}

= 2^{2} (x^{- 1})^{2} (y^{2})^{2}

2^{2} = 4

= 4 (x^{- 1})^{2} (y^{2})^{2}

Vereinfache

(x^{- 1})^{2} : \frac{1}{x ^{2}}

= 4 \cdot \frac{1}{x ^{2}} (y^{2})^{2}

Vereinfache

(y^{2})^{2} : y^{4}

= 4 \cdot \frac{1}{x ^{2}} y^{4}

Vereinfache

4 \cdot \frac{1}{x ^{2}} y^{4} : \frac{4 y ^{4}}{x ^{2}}

= \frac{4 y ^{4}}{x ^{2}}

e x p an d (m^{2} - 2)^{3}

f a c t or - n^{2} + n + 20

s im pl i f y \frac{2}{7 - 6}

e x p an d (x^{2} + x - 1) (2 x^{2} - x + 2)

s im pl i f y \frac{- 80}{10}