What is (4x^2-x-3)-(x^2+2x-5) ?

The solution to (4x^2-x-3)-(x^2+2x-5) is 3x^2-3x+2

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simplify (4x^2-x-3)-(x^2+2x-5)

simplify

(4 x^{2} - x - 3) - (x^{2} + 2 x - 5)

3 x^{2} - 3 x + 2

Solution steps

(4 x^{2} - x - 3) - (x^{2} + 2 x - 5)

Apply rule:

(a) = a

(4 x^{2} - x - 3) = 4 x^{2} - x - 3

= 4 x^{2} - x - 3 - (x^{2} + 2 x - 5)

Apply the distributive law:

- (a + b) = - a - b

- (x^{2} + 2 x - 5) = - x^{2} - 2 x + 5

= 4 x^{2} - x - 3 - x^{2} - 2 x + 5

Group like terms

= 4 x^{2} - x^{2} - x - 2 x - 3 + 5

Add similar elements:

4 x^{2} - x^{2} = 3 x^{2}

= 3 x^{2} - x - 2 x - 3 + 5

Add similar elements:

- x - 2 x = - 3 x

= 3 x^{2} - 3 x - 3 + 5

Add the numbers:

- 3 + 5 = 2

= 3 x^{2} - 3 x + 2

(\frac{4}{4 ^{- 3}})^{- 2}

\frac{8}{9} - \frac{5}{9}

4 (x - 4) - 7 x

\frac{3}{14}

What is (4x^2-x-3)-(x^2+2x-5) ?
The solution to (4x^2-x-3)-(x^2+2x-5) is 3x^2-3x+2