What is ((4k^6)/(2k^2))^4 ?

The solution to ((4k^6)/(2k^2))^4 is 16k^{16}

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simplify ((4k^6)/(2k^2))^4

simplify

(\frac{4 k ^{6}}{2 k ^{2}})^{4}

16 k^{16}

Solution steps

(\frac{4 k ^{6}}{2 k ^{2}})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 4 k ^{6} ) ^{4}}{( 2 k ^{2} ) ^{4}}

Simplify

(4 k^{6})^{4} : 256 k^{24}

= \frac{256 k ^{24}}{( 2 k ^{2} ) ^{4}}

Simplify

(2 k^{2})^{4} : 16 k^{8}

= \frac{256 k ^{24}}{16 k ^{8}}

Divide the numbers:

\frac{256}{16} = 16

= \frac{16 k ^{24}}{k ^{8}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{k ^{24}}{k ^{8}} = k^{24 - 8}

= 16 k^{24 - 8}

Subtract the numbers:

24 - 8 = 16

= 16 k^{16}

(7 x^{2} + 4 y^{3}) (7 x^{2} - 4 y^{3})

(x + 2)^{2} - 7 (x + 2) + 6

4^{2} \cdot 4^{2} 29

e^{2 (l n (3))}

(x + 2)^{3} + (x - 4)^{2} + 5 (x - 3)