What is (x^2-3x+4)-(4x^2-5x-1) ?

The solution to (x^2-3x+4)-(4x^2-5x-1) is -3x^2+2x+5

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simplify (x^2-3x+4)-(4x^2-5x-1)

simplify

(x^{2} - 3 x + 4) - (4 x^{2} - 5 x - 1)

- 3 x^{2} + 2 x + 5

Solution steps

(x^{2} - 3 x + 4) - (4 x^{2} - 5 x - 1)

Apply rule:

(a) = a

(x^{2} - 3 x + 4) = x^{2} - 3 x + 4

= x^{2} - 3 x + 4 - (4 x^{2} - 5 x - 1)

Apply the distributive law:

- (a - b) = - a + b

- (4 x^{2} - 5 x - 1) = - 4 x^{2} + 5 x + 1

= x^{2} - 3 x + 4 - 4 x^{2} + 5 x + 1

Group like terms

= x^{2} - 4 x^{2} - 3 x + 5 x + 4 + 1

Add similar elements:

x^{2} - 4 x^{2} = - 3 x^{2}

= - 3 x^{2} - 3 x + 5 x + 4 + 1

Add similar elements:

- 3 x + 5 x = 2 x

= - 3 x^{2} + 2 x + 4 + 1

Add the numbers:

4 + 1 = 5

= - 3 x^{2} + 2 x + 5

7 x + 3 - 5 x + 8 + 4 x - 1

8 w - 10

2^{2 x^{2}}

\frac{75}{9}

\frac{3}{7} \cdot \frac{9}{4}

What is (x^2-3x+4)-(4x^2-5x-1) ?
The solution to (x^2-3x+4)-(4x^2-5x-1) is -3x^2+2x+5