What is \sqrt[5]{\sqrt[3]{2^8}} ?

The solution to \sqrt[5]{\sqrt[3]{2^8}} is \sqrt[15]{4^4}

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simplify \sqrt[5]{\sqrt[3]{2^8}}

simplify

Decimal Notation

1.44726 \dots

Solution steps

2^{2} = 4

Apply radical rule:

= 4^{\frac{1}{5}} \cdot 4^{\frac{1}{15}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

4^{\frac{1}{5}} \cdot 4^{\frac{1}{15}} = 4^{\frac{1}{5} + \frac{1}{15}}

= 4^{\frac{1}{5} + \frac{1}{15}}

\frac{1}{5} + \frac{1}{15} = \frac{4}{15}

= 4^{\frac{4}{15}}

12 x^{6} - 7 x^{3} y - 10 y^{2}

\frac{4}{7} - \frac{2}{3}

1 - 121 x^{4} y^{4}

35 \cdot 45

35 \cdot 42

What is \sqrt[5]{\sqrt[3]{2^8}} ?
The solution to \sqrt[5]{\sqrt[3]{2^8}} is \sqrt[15]{4^4}