簡約 (2(1.9)+1)/(log_{2)(1.9)}

解

簡約

\frac{2 ( 1.9 ) + 1}{lo g _{2} ( 1.9 )}

\frac{24}{5 ( lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 ) )}

十進法表記

5.18358 \dots

解答ステップ

\frac{2 ( 1.9 ) + 1}{lo g _{2} ( 1.9 )}

規則を適用する:

(a) = a

(1.9) = 1.9

= \frac{2 \cdot 1.9 + 1}{lo g _{2} ( 1.9 )}

2 \cdot 1.9 + 1 = 4.8

= \frac{4.8}{lo g _{2} ( 1.9 )}

lo g_{2} (1.9) = lo g_{2} (19) - 1 - lo g_{2} (5)

= \frac{4.8}{lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 )}

\frac{4.8}{lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 )} = \frac{48}{10 ( lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 ) )}

= \frac{48}{10 ( lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 ) )}

キャンセル

\frac{48}{10 ( lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 ) )} : \frac{24}{5 ( lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 ) )}

= \frac{24}{5 ( lo g _{2} ( 19 ) - 1 - lo g _{2} ( 5 ) )}