log_{2}((x+4)^2)=4

解答

lo g_{2} ((x + 4)^{2}) = 4

x = 0, x = - 8

求解步骤

lo g_{2} ((x + 4)^{2}) = 4

使用对数运算法则

(x + 4)^{2} = 16

解

(x + 4)^{2} = 16 : x = 0, x = - 8

x = 0, x = - 8

1 + lo g_{10} (x) = lo g_{10} (x + 1)

ln (x - 2) + ln (x + 2) = ln (3 x)

lo g_{9} (x + 1) - lo g_{9} (1 - x) = lo g_{9} (2 x + 3)

so l v e f or u, ln (1 - u) = x

ln (ln (x)) = 1