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Beliebt Algebra >

|2x-3|+|2x+1|+|2x+5|=12

Lösung

∣ 2 x - 3 ∣ + ∣ 2 x + 1 ∣ + ∣ 2 x + 5 ∣ = 12

Lösung

x = - \frac{5}{2} or x = \frac{3}{2}

+1

Dezimale

x = - 2.5, x = 1.5

Schritte zur Lösung

∣ 2 x - 3 ∣ + ∣ 2 x + 1 ∣ + ∣ 2 x + 5 ∣ = 12

Finde positive und negative Intervalle

x < - \frac{5}{2}, - \frac{5}{2} \leq x < - \frac{1}{2}, - \frac{1}{2} \leq x < \frac{3}{2}, x \geq \frac{3}{2}

Löse die Ungleichung für jedes Intervall

keine L \overset{o}{¨} sung or x = - \frac{5}{2} or x = \frac{3}{2}

x = - \frac{5}{2} or x = \frac{3}{2}

Graph

Beliebte Beispiele

5 ∣ x + 3 ∣ - 1 = 6

|2x-3|-|x^2-4x+3|=|x^2-2x|

∣ 2 x - 3 ∣ - x^{2} - 4 x + 3 = x^{2} - 2 x

|x^2-x|+|x+1|=5

x^{2} - x + ∣ x + 1 ∣ = 5

∣ x ∣ + ∣ y ∣ = 4

∣ x ∣ + x^{3} = 0