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受欢迎的代数 >

3.2+2*t=0.23t^2

解答

3.2 + 2 \cdot t = 0.23 t^{2}

解答

t = \frac{4 ( 25 + 1085 )}{23}, t = \frac{4 ( 25 - 1085 )}{23}

+1

十进制

t = 10.07640 \dots, t = - 1.38075 \dots

求解步骤

3.2 + 2 t = 0.23 t^{2}

在两边乘以

100

320 + 200 t = 23 t^{2}

交换两边

23 t^{2} = 320 + 200 t

将

200 t

para o lado esquerdo

23 t^{2} - 200 t = 320

将

320

para o lado esquerdo

23 t^{2} - 200 t - 320 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 23 ( - 320 )}{2 \cdot 23}

(- 200)^{2} - 4 \cdot 23 (- 320) = 81085

t_{1, 2} = \frac{- ( - 200 ) \pm 8 1085}{2 \cdot 23}

将解分隔开

t_{1} = \frac{- ( - 200 ) + 8 1085}{2 \cdot 23}, t_{2} = \frac{- ( - 200 ) - 8 1085}{2 \cdot 23}

t = \frac{- ( - 200 ) + 8 1085}{2 \cdot 23} : \frac{4 ( 25 + 1085 )}{23}

t = \frac{- ( - 200 ) - 8 1085}{2 \cdot 23} : \frac{4 ( 25 - 1085 )}{23}

二次方程组的解是:

t = \frac{4 ( 25 + 1085 )}{23}, t = \frac{4 ( 25 - 1085 )}{23}

作图

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