((2x^2+9x-5))/((x^4+1))=0

解

\frac{( 2 x ^{2} + 9 x - 5 )}{( x ^{4} + 1 )} = 0

x = \frac{1}{2}, x = - 5

十進法表記

x = 0.5, x = - 5

解答ステップ

\frac{( 2 x ^{2} + 9 x - 5 )}{( x ^{4} + 1 )} = 0

簡素化

\frac{( 2 x ^{2} + 9 x - 5 )}{( x ^{4} + 1 )} : \frac{2 x ^{2} + 9 x - 5}{x ^{4} + 1}

\frac{2 x ^{2} + 9 x - 5}{x ^{4} + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x^{2} + 9 x - 5 = 0

解く

2 x^{2} + 9 x - 5 = 0 : x = \frac{1}{2}, x = - 5

x = \frac{1}{2}, x = - 5