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Frequently Asked Questions (FAQ)
What are the solutions to the equation -96z^2=-48 ?
- The solutions to the equation -96z^2=-48 are z= 1/(sqrt(2)),z=-1/(sqrt(2))
Find the zeros of -96z^2=-48
- The zeros of -96z^2=-48 are z= 1/(sqrt(2)),z=-1/(sqrt(2))